3.969 \(\int (b x)^{5/2} (\pi +d x)^n (e+f x)^p \, dx\)

Optimal. Leaf size=63 \[ \frac{2 \pi ^n (b x)^{7/2} (e+f x)^p \left (\frac{f x}{e}+1\right )^{-p} F_1\left (\frac{7}{2};-n,-p;\frac{9}{2};-\frac{d x}{\pi },-\frac{f x}{e}\right )}{7 b} \]

[Out]

(2*Pi^n*(b*x)^(7/2)*(e + f*x)^p*AppellF1[7/2, -n, -p, 9/2, -((d*x)/Pi), -((f*x)/e)])/(7*b*(1 + (f*x)/e)^p)

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Rubi [A]  time = 0.0293217, antiderivative size = 63, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.091, Rules used = {135, 133} \[ \frac{2 \pi ^n (b x)^{7/2} (e+f x)^p \left (\frac{f x}{e}+1\right )^{-p} F_1\left (\frac{7}{2};-n,-p;\frac{9}{2};-\frac{d x}{\pi },-\frac{f x}{e}\right )}{7 b} \]

Antiderivative was successfully verified.

[In]

Int[(b*x)^(5/2)*(Pi + d*x)^n*(e + f*x)^p,x]

[Out]

(2*Pi^n*(b*x)^(7/2)*(e + f*x)^p*AppellF1[7/2, -n, -p, 9/2, -((d*x)/Pi), -((f*x)/e)])/(7*b*(1 + (f*x)/e)^p)

Rule 135

Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_Symbol] :> Dist[(c^IntPart[n]*(c +
d*x)^FracPart[n])/(1 + (d*x)/c)^FracPart[n], Int[(b*x)^m*(1 + (d*x)/c)^n*(e + f*x)^p, x], x] /; FreeQ[{b, c, d
, e, f, m, n, p}, x] &&  !IntegerQ[m] &&  !IntegerQ[n] &&  !GtQ[c, 0]

Rule 133

Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_Symbol] :> Simp[(c^n*e^p*(b*x)^(m +
1)*AppellF1[m + 1, -n, -p, m + 2, -((d*x)/c), -((f*x)/e)])/(b*(m + 1)), x] /; FreeQ[{b, c, d, e, f, m, n, p},
x] &&  !IntegerQ[m] &&  !IntegerQ[n] && GtQ[c, 0] && (IntegerQ[p] || GtQ[e, 0])

Rubi steps

\begin{align*} \int (b x)^{5/2} (\pi +d x)^n (e+f x)^p \, dx &=\left ((e+f x)^p \left (1+\frac{f x}{e}\right )^{-p}\right ) \int (b x)^{5/2} (\pi +d x)^n \left (1+\frac{f x}{e}\right )^p \, dx\\ &=\frac{2 \pi ^n (b x)^{7/2} (e+f x)^p \left (1+\frac{f x}{e}\right )^{-p} F_1\left (\frac{7}{2};-n,-p;\frac{9}{2};-\frac{d x}{\pi },-\frac{f x}{e}\right )}{7 b}\\ \end{align*}

Mathematica [A]  time = 0.0709525, size = 62, normalized size = 0.98 \[ \frac{2}{7} \pi ^n x (b x)^{5/2} (e+f x)^p \left (\frac{e+f x}{e}\right )^{-p} F_1\left (\frac{7}{2};-n,-p;\frac{9}{2};-\frac{d x}{\pi },-\frac{f x}{e}\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[(b*x)^(5/2)*(Pi + d*x)^n*(e + f*x)^p,x]

[Out]

(2*Pi^n*x*(b*x)^(5/2)*(e + f*x)^p*AppellF1[7/2, -n, -p, 9/2, -((d*x)/Pi), -((f*x)/e)])/(7*((e + f*x)/e)^p)

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Maple [F]  time = 0.043, size = 0, normalized size = 0. \begin{align*} \int \left ( bx \right ) ^{{\frac{5}{2}}} \left ( dx+\pi \right ) ^{n} \left ( fx+e \right ) ^{p}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x)^(5/2)*(d*x+Pi)^n*(f*x+e)^p,x)

[Out]

int((b*x)^(5/2)*(d*x+Pi)^n*(f*x+e)^p,x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (b x\right )^{\frac{5}{2}}{\left (\pi + d x\right )}^{n}{\left (f x + e\right )}^{p}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x)^(5/2)*(d*x+pi)^n*(f*x+e)^p,x, algorithm="maxima")

[Out]

integrate((b*x)^(5/2)*(pi + d*x)^n*(f*x + e)^p, x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\sqrt{b x}{\left (\pi + d x\right )}^{n}{\left (f x + e\right )}^{p} b^{2} x^{2}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x)^(5/2)*(d*x+pi)^n*(f*x+e)^p,x, algorithm="fricas")

[Out]

integral(sqrt(b*x)*(pi + d*x)^n*(f*x + e)^p*b^2*x^2, x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x)**(5/2)*(d*x+pi)**n*(f*x+e)**p,x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (b x\right )^{\frac{5}{2}}{\left (\pi + d x\right )}^{n}{\left (f x + e\right )}^{p}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x)^(5/2)*(d*x+pi)^n*(f*x+e)^p,x, algorithm="giac")

[Out]

integrate((b*x)^(5/2)*(pi + d*x)^n*(f*x + e)^p, x)